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SQL语句中多表Count

除了count之外还有一个函数叫做 SUM。 SELECT paperName , COUNT (1) AS 总题数 , sum (CASE WHEN statu = 1 THEN 1 ELSE 0 END) AS 审核题数FROM questionGROUP BY paperNmepapername in(select distinct paperName from question) 这个没意义...

select tat.id ,tat.name ,count(tbt.id) as numbersd from test_a_temp tat,test_b_temp tbt where tbt.no=tat.id group by tat.id,tat.name order by numbersd desc 其中 test_a_temp 就是你那个A表,test_b_temp 就是B表 A中有两列 ID,NAME ...

可以通过count函数来实现。 sqlOne:select * from tablename1 where id>5;此语句查询出来多条记录,之后看做一个新的表。 sqlTwo:select conut(*) from (select * from tablename1 where id>5) as tablename2;此语句即可查询出来统计的记录条...

select top 10 n.*,d.p from new n, (select count(*) as p,newId from comment group by newId) d where n.newId=@id and n.newId = d.newId order by d.p desc

可以有两种解决方法, 所需工具:SQL 查询两个count的方法1: SELECT paperName , COUNT (1) AS 总题数 , sum (CASE WHEN statu = 1 THEN 1 ELSE 0 END) AS 审核题数FROM questionGROUP BY paperNme 查询两个count的方法2: select s.总题数, s.审...

可以有两种解决方法。 方法1: SELECT paperName , COUNT (1) AS 总题数 , sum (CASE WHEN statu = 1 THEN 1 ELSE 0 END) AS 审核题数 FROM question GROUP BY paperNme 方法2: select s.总题数, s.审核题数, s.paperName from ( select COUNT(...

select a.content ,count(u.articleId)from article a,user u where a.id = u.articleId and a.artilceName = 'pumpkin'

COUNT() 函数返回匹配指定条件的行数。 SQL COUNT(column_name) 语法 COUNT(column_name) 函数返回指定列的值的数目(NULL 不计入): SELECT COUNT(column_name) FROM table_name; SQL COUNT(*) 语法 COUNT(*) 函数返回表中的记录数: SELECT C...

用分组,组内计数就可以了,意思就是根据字段a的取值进行分组,相同的为一组,在用count进行组内计数。 select a,count(*) from A group by a 扩展资料:SQL统计重复数据 1、生成表 CREATE TABLE TEST1 ( COL1 CHAR(2), COL2 INT ) GO 2、插入数...

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