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sql中多表查询 还有COUNT

select a. col1, b.col2 from (select count(id) as col1 from table1) as a, (select count(id) as col2 from table2) as b -------------这样写。

可以这样写: select (select count(*) from bumen)+(select count(*) from mrs) as sum_count 如果两个表结果相同的话,也可以用 select count(*) as sum_count from ( select * from A union all select * from B ) as tmp

select tat.id ,tat.name ,count(tbt.id) as numbersd from test_a_temp tat,test_b_temp tbt where tbt.no=tat.id group by tat.id,tat.name order by numbersd desc 其中 test_a_temp 就是你那个A表,test_b_temp 就是B表 A中有两列 ID,NAME ...

可以有两种解决方法。 方法1: SELECT paperName , COUNT (1) AS 总题数 , sum (CASE WHEN statu = 1 THEN 1 ELSE 0 END) AS 审核题数 FROM question GROUP BY paperNme 方法2: select s.总题数, s.审核题数, s.paperName from ( select COUNT(...

首先这个应该是外连接查询。你知道你错在何处吗?你要查询所有的news,为什么还要限定n.newsid=@ID,你这样查询的只有一条记录了。 select top 10 n.newid,count(c.*) from new as n left jion conmment as c on n.newid=c.newid group by n.newid...

在最后的地方 随便加个字符, ) a就可以了。缺少一个表名,相当于。 select sum(tmpcount) from ( select count(*) as tmpcount from tab1 union all select count(*) as tmpcount from tab2) a具体如下: 1、简介 结构化查询语言(Structured Qu...

select a.栏目,count(b.文章) from sortlist a,article b where a.sortid=b.sortid group by a.栏目;

select ISNULL(a.id,b.id) as memberid,ISNULL(a.a1,0) as albumcount,ISNULL(b.a1,0) as lOGcount from ( select m.id,COUNT(1) as a1 from member m inner join album a on a.id=m.id group by m.id)a full join (select m.id,COUNT(1) as a1 ...

可以通过count函数来实现。 sqlOne:select * from tablename1 where id>5;此语句查询出来多条记录,之后看做一个新的表。 sqlTwo:select conut(*) from (select * from tablename1 where id>5) as tablename2;此语句即可查询出来统计的记录条...

select a.content ,count(u.articleId)from article a,user u where a.id = u.articleId and a.artilceName = 'pumpkin'

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